Optimal. Leaf size=310 \[ \frac{e^3 (a+b x) \log (a+b x) (-5 a B e+A b e+4 b B d)}{b^6 \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{2 e^2 (b d-a e) (-5 a B e+2 A b e+3 b B d)}{b^6 \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{e (b d-a e)^2 (-5 a B e+3 A b e+2 b B d)}{b^6 (a+b x) \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{(b d-a e)^3 (-5 a B e+4 A b e+b B d)}{3 b^6 (a+b x)^2 \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{(A b-a B) (b d-a e)^4}{4 b^6 (a+b x)^3 \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{B e^4 x (a+b x)}{b^5 \sqrt{a^2+2 a b x+b^2 x^2}} \]
[Out]
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Rubi [A] time = 0.744448, antiderivative size = 310, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 33, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.061 \[ \frac{e^3 (a+b x) \log (a+b x) (-5 a B e+A b e+4 b B d)}{b^6 \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{2 e^2 (b d-a e) (-5 a B e+2 A b e+3 b B d)}{b^6 \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{e (b d-a e)^2 (-5 a B e+3 A b e+2 b B d)}{b^6 (a+b x) \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{(b d-a e)^3 (-5 a B e+4 A b e+b B d)}{3 b^6 (a+b x)^2 \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{(A b-a B) (b d-a e)^4}{4 b^6 (a+b x)^3 \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{B e^4 x (a+b x)}{b^5 \sqrt{a^2+2 a b x+b^2 x^2}} \]
Antiderivative was successfully verified.
[In] Int[((A + B*x)*(d + e*x)^4)/(a^2 + 2*a*b*x + b^2*x^2)^(5/2),x]
[Out]
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Rubi in Sympy [A] time = 46.2883, size = 314, normalized size = 1.01 \[ \frac{B \left (2 a + 2 b x\right ) \left (d + e x\right )^{5}}{2 b e \left (a^{2} + 2 a b x + b^{2} x^{2}\right )^{\frac{5}{2}}} + \frac{\left (2 a + 2 b x\right ) \left (d + e x\right )^{4} \left (- A b e + B \left (5 a e - 4 b d\right )\right )}{8 b^{2} e \left (a^{2} + 2 a b x + b^{2} x^{2}\right )^{\frac{5}{2}}} + \frac{\left (d + e x\right )^{3} \left (- A b e + B \left (5 a e - 4 b d\right )\right )}{3 b^{3} \left (a^{2} + 2 a b x + b^{2} x^{2}\right )^{\frac{3}{2}}} + \frac{e \left (2 a + 2 b x\right ) \left (d + e x\right )^{2} \left (- A b e + B \left (5 a e - 4 b d\right )\right )}{4 b^{4} \left (a^{2} + 2 a b x + b^{2} x^{2}\right )^{\frac{3}{2}}} + \frac{e^{2} \left (d + e x\right ) \left (- A b e + B \left (5 a e - 4 b d\right )\right )}{b^{5} \sqrt{a^{2} + 2 a b x + b^{2} x^{2}}} - \frac{e^{3} \left (a + b x\right ) \left (- A b e + B \left (5 a e - 4 b d\right )\right ) \log{\left (a + b x \right )}}{b^{6} \sqrt{a^{2} + 2 a b x + b^{2} x^{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((B*x+A)*(e*x+d)**4/(b**2*x**2+2*a*b*x+a**2)**(5/2),x)
[Out]
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Mathematica [A] time = 0.414344, size = 331, normalized size = 1.07 \[ \frac{-A b (b d-a e) \left (25 a^3 e^3+a^2 b e^2 (13 d+88 e x)+a b^2 e \left (7 d^2+40 d e x+108 e^2 x^2\right )+b^3 \left (3 d^3+16 d^2 e x+36 d e^2 x^2+48 e^3 x^3\right )\right )-B \left (77 a^5 e^4+4 a^4 b e^3 (62 e x-25 d)+2 a^3 b^2 e^2 \left (9 d^2-176 d e x+126 e^2 x^2\right )+4 a^2 b^3 e \left (d^3+18 d^2 e x-108 d e^2 x^2+12 e^3 x^3\right )+a b^4 \left (d^4+16 d^3 e x+108 d^2 e^2 x^2-192 d e^3 x^3-48 e^4 x^4\right )+4 b^5 x \left (d^4+6 d^3 e x+18 d^2 e^2 x^2-3 e^4 x^4\right )\right )+12 e^3 (a+b x)^4 \log (a+b x) (-5 a B e+A b e+4 b B d)}{12 b^6 (a+b x)^3 \sqrt{(a+b x)^2}} \]
Antiderivative was successfully verified.
[In] Integrate[((A + B*x)*(d + e*x)^4)/(a^2 + 2*a*b*x + b^2*x^2)^(5/2),x]
[Out]
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Maple [B] time = 0.029, size = 735, normalized size = 2.4 \[{\frac{ \left ( 12\,A\ln \left ( bx+a \right ){a}^{4}b{e}^{4}+88\,Ax{a}^{3}{b}^{2}{e}^{4}-252\,B{x}^{2}{a}^{3}{b}^{2}{e}^{4}+48\,B{x}^{4}a{b}^{4}{e}^{4}+48\,A{x}^{3}a{b}^{4}{e}^{4}-3\,A{b}^{5}{d}^{4}+288\,B\ln \left ( bx+a \right ){x}^{2}{a}^{2}{b}^{3}d{e}^{3}+192\,B\ln \left ( bx+a \right ) x{a}^{3}{b}^{2}d{e}^{3}-24\,B{x}^{2}{b}^{5}{d}^{3}e+12\,A\ln \left ( bx+a \right ){x}^{4}{b}^{5}{e}^{4}-36\,A{x}^{2}{b}^{5}{d}^{2}{e}^{2}-48\,Ax{a}^{2}{b}^{3}d{e}^{3}+25\,A{a}^{4}b{e}^{4}-4\,Aa{b}^{4}{d}^{3}e-Ba{b}^{4}{d}^{4}-4\,B{a}^{2}{b}^{3}{d}^{3}e-4\,Bx{b}^{5}{d}^{4}+12\,B{x}^{5}{b}^{5}{e}^{4}-60\,B\ln \left ( bx+a \right ){a}^{5}{e}^{4}-77\,B{a}^{5}{e}^{4}-48\,A{x}^{3}{b}^{5}d{e}^{3}-48\,B{x}^{3}{a}^{2}{b}^{3}{e}^{4}-72\,B{x}^{3}{b}^{5}{d}^{2}{e}^{2}-248\,Bx{a}^{4}b{e}^{4}+108\,A{x}^{2}{a}^{2}{b}^{3}{e}^{4}-16\,Ax{b}^{5}{d}^{3}e-60\,B\ln \left ( bx+a \right ){x}^{4}a{b}^{4}{e}^{4}+48\,B\ln \left ( bx+a \right ){x}^{4}{b}^{5}d{e}^{3}+48\,A\ln \left ( bx+a \right ){x}^{3}a{b}^{4}{e}^{4}-240\,B\ln \left ( bx+a \right ){x}^{3}{a}^{2}{b}^{3}{e}^{4}+192\,B{x}^{3}a{b}^{4}d{e}^{3}-72\,A{x}^{2}a{b}^{4}d{e}^{3}-24\,Axa{b}^{4}{d}^{2}{e}^{2}-16\,Bxa{b}^{4}{d}^{3}e+72\,A\ln \left ( bx+a \right ){x}^{2}{a}^{2}{b}^{3}{e}^{4}-360\,B\ln \left ( bx+a \right ){x}^{2}{a}^{3}{b}^{2}{e}^{4}+48\,A\ln \left ( bx+a \right ) x{a}^{3}{b}^{2}{e}^{4}-240\,B\ln \left ( bx+a \right ) x{a}^{4}b{e}^{4}+48\,B\ln \left ( bx+a \right ){a}^{4}bd{e}^{3}+352\,Bx{a}^{3}{b}^{2}d{e}^{3}-72\,Bx{a}^{2}{b}^{3}{d}^{2}{e}^{2}+432\,B{x}^{2}{a}^{2}{b}^{3}d{e}^{3}-108\,B{x}^{2}a{b}^{4}{d}^{2}{e}^{2}-18\,B{a}^{3}{b}^{2}{d}^{2}{e}^{2}-12\,A{a}^{3}{b}^{2}d{e}^{3}+100\,B{a}^{4}bd{e}^{3}+192\,B\ln \left ( bx+a \right ){x}^{3}a{b}^{4}d{e}^{3}-6\,A{a}^{2}{b}^{3}{d}^{2}{e}^{2} \right ) \left ( bx+a \right ) }{12\,{b}^{6}} \left ( \left ( bx+a \right ) ^{2} \right ) ^{-{\frac{5}{2}}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((B*x+A)*(e*x+d)^4/(b^2*x^2+2*a*b*x+a^2)^(5/2),x)
[Out]
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Maxima [A] time = 0.792554, size = 1149, normalized size = 3.71 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)*(e*x + d)^4/(b^2*x^2 + 2*a*b*x + a^2)^(5/2),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.299749, size = 836, normalized size = 2.7 \[ \frac{12 \, B b^{5} e^{4} x^{5} + 48 \, B a b^{4} e^{4} x^{4} -{\left (B a b^{4} + 3 \, A b^{5}\right )} d^{4} - 4 \,{\left (B a^{2} b^{3} + A a b^{4}\right )} d^{3} e - 6 \,{\left (3 \, B a^{3} b^{2} + A a^{2} b^{3}\right )} d^{2} e^{2} + 4 \,{\left (25 \, B a^{4} b - 3 \, A a^{3} b^{2}\right )} d e^{3} -{\left (77 \, B a^{5} - 25 \, A a^{4} b\right )} e^{4} - 24 \,{\left (3 \, B b^{5} d^{2} e^{2} - 2 \,{\left (4 \, B a b^{4} - A b^{5}\right )} d e^{3} + 2 \,{\left (B a^{2} b^{3} - A a b^{4}\right )} e^{4}\right )} x^{3} - 12 \,{\left (2 \, B b^{5} d^{3} e + 3 \,{\left (3 \, B a b^{4} + A b^{5}\right )} d^{2} e^{2} - 6 \,{\left (6 \, B a^{2} b^{3} - A a b^{4}\right )} d e^{3} + 3 \,{\left (7 \, B a^{3} b^{2} - 3 \, A a^{2} b^{3}\right )} e^{4}\right )} x^{2} - 4 \,{\left (B b^{5} d^{4} + 4 \,{\left (B a b^{4} + A b^{5}\right )} d^{3} e + 6 \,{\left (3 \, B a^{2} b^{3} + A a b^{4}\right )} d^{2} e^{2} - 4 \,{\left (22 \, B a^{3} b^{2} - 3 \, A a^{2} b^{3}\right )} d e^{3} + 2 \,{\left (31 \, B a^{4} b - 11 \, A a^{3} b^{2}\right )} e^{4}\right )} x + 12 \,{\left (4 \, B a^{4} b d e^{3} -{\left (5 \, B a^{5} - A a^{4} b\right )} e^{4} +{\left (4 \, B b^{5} d e^{3} -{\left (5 \, B a b^{4} - A b^{5}\right )} e^{4}\right )} x^{4} + 4 \,{\left (4 \, B a b^{4} d e^{3} -{\left (5 \, B a^{2} b^{3} - A a b^{4}\right )} e^{4}\right )} x^{3} + 6 \,{\left (4 \, B a^{2} b^{3} d e^{3} -{\left (5 \, B a^{3} b^{2} - A a^{2} b^{3}\right )} e^{4}\right )} x^{2} + 4 \,{\left (4 \, B a^{3} b^{2} d e^{3} -{\left (5 \, B a^{4} b - A a^{3} b^{2}\right )} e^{4}\right )} x\right )} \log \left (b x + a\right )}{12 \,{\left (b^{10} x^{4} + 4 \, a b^{9} x^{3} + 6 \, a^{2} b^{8} x^{2} + 4 \, a^{3} b^{7} x + a^{4} b^{6}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)*(e*x + d)^4/(b^2*x^2 + 2*a*b*x + a^2)^(5/2),x, algorithm="fricas")
[Out]
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Sympy [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{\left (A + B x\right ) \left (d + e x\right )^{4}}{\left (\left (a + b x\right )^{2}\right )^{\frac{5}{2}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x+A)*(e*x+d)**4/(b**2*x**2+2*a*b*x+a**2)**(5/2),x)
[Out]
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GIAC/XCAS [A] time = 0.677745, size = 4, normalized size = 0.01 \[ \mathit{sage}_{0} x \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)*(e*x + d)^4/(b^2*x^2 + 2*a*b*x + a^2)^(5/2),x, algorithm="giac")
[Out]